Sunday, January 31, 2010

Belly Flop 12 M 30 Cm Physics Collision And Impulse?

Physics Collision and Impulse? - belly flop 12 m 30 cm

Until the seventies, Henri LaMothe excited belly-flop from a height of 12 m in 30 cm of water. Under the assumption that prevents it is enough if the bottom of the water and estimate the mass to determine the size of the dynamics of the water.

1 comment:

heartsen... said...

Impulse = change in time

If Henry 12 meters. How long does it take until autumn is t.

12 = (1 / 2) gt ^ 2 = (0.5) (9.8) t ^ 2

t = sqrt [12 / (0.5) (9.8)] = 1.56 seconds

At this time, to achieve a gross or (9.8) (1.56) = 15.3 m / sec

Under the assumption that weighs 100 kg, we can now calculate your initial impulse, the mv or (100) (15.3) or m-kg/sec 1520

His last sentence is zero, so that the water is only 1520 m-kg/sec Dynamics

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